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Answer is D
Explanation
We know that pH=−log[H^+]
pH=8
Thus, 8= −log[H^+]
Hence [H+]=10^−8
Thus, concentration of H^+ is 10^−8M
Answer is D
Explanation
We know that pH=−log[H^+]
pH=8
Thus, 8= −log[H^+]
Hence [H+]=10^−8
Thus, concentration of H^+ is 10^−8M