Answer:
a.
[tex]Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}[/tex]
b.
[tex]Keq=[O_2]^3[/tex]
c.
[tex]Keq=\frac{[H_3O^+][F^-]}{[HF]}[/tex]
d.
[tex]Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}[/tex]
Explanation:
Hello there!
In this case, for the attached reactions, it turns out possible for us to write the equilibrium expressions by knowing any liquid or solid would be not-included in the equilibrium expression as shown below, with the general form products/reactants:
a.
[tex]Keq=\frac{[HCO_3^-][OH^-]}{[CO_3^{2-}]}[/tex]
b.
[tex]Keq=[O_2]^3[/tex]
c.
[tex]Keq=\frac{[H_3O^+][F^-]}{[HF]}[/tex]
d.
[tex]Keq=\frac{[NH_4^+][OH^-]}{[NH_3]}[/tex]
Regards!
