Respuesta :
You could use recursion to write java method for computing fibonacci numbers. Though it will be inefficient for n > about 50, it will work.
public static int fibonacci(int n) {
if (n < 0) { return -1; }
if (n < 2) { return n; }
else { return fibonacci(n-1)+fibonacci(n-2); }
}
Hope this helps.
The current term of a Fibonacci series is derived by adding the two previous terms of its sequence; and the first two terms are 0 and 1.
The code segment (without comments) that completes the program is as follows:
int T1 = 0, T2 = 1, cT;
if (n < 0){
return -1; }
for (int i = 2; i <= n; i++) {
cT = T1 + T2;
T1 = T2;
T2 = cT; }
return T2;
With comments (to explain each line)
/*This declares the first term (T1), the second term (T2) and the current term (CT).
T1 and T2 are also initialized to 0 and 1, respectively
*/
int T1 = 0, T2 = 1, cT;
//This returns -1, if n is negative
if (n < 0){ return -1;
}
//The following iterates through n
for (int i = 2; i <= n; i++) {
//This calculates cT
cT = T1 + T2;
//This passes T2 to T1
T1 = T2;
//This passes cT to T2
T2 = cT;
}
//This returns the required term of the Fibonacci series
return T2;
At the end of the program, the nth term of the series would be returned to the main method for output.
Read more about Fibonacci series at:
https://brainly.com/question/24110383