Answer:
[tex] \frac{8}{3} c - 2 = \frac{2}{3} c - 12[/tex]
add 2 to both sides:
[tex]( \frac{8}{3} c - 2) + 2 = ( \frac{2}{3} c - 12) + 2 \\ \\ \frac{8}{3} c = \frac{2}{ 3} c - 10[/tex]
collect c terms on both sides:
[tex] \frac{8}{3} c - \frac{2}{3} c = - 10 \\ \\ \{\frac{(8 - 2)}{3} \}c = - 10 \\ \\ \frac{6}{3} c = - 10 \\ \\ 2c = - 10 \\ { \boxed{ \boxed{c = - 5}}}[/tex]
