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[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

  • Find x.

[tex] \large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}[/tex]

To solve these type of problems you need to use the pythagoras theorem ⇨ Hypotenuse² = Base² + Altitude².

Here,

  • Altitude = 1.6 cm.
  • Base = 1.2 cm
  • Hypotenuse = x

Now, let's solve for x.

Hypotenuse² = Base² + Altitude²

x² = (1.2)² + (1.6)²

x² = 1.44 + 2.56

x² = 4

x = √4

x = 2.

So, the value of x is 2 cm.

NOTE :-

  • Pythagoras theorem can be used only in the cases of right-angled triangles. Here, it's given that the triangle is right angled so we can use this theorem.
  • To solve the squares if decimals, take them as whole numbers & then just add the decimal points. For example, ⇨ for (1.2)², take it as 12² , then multiply 12 by 12, you'll get 144. Now, add the decimal place accordingly ⇨ 1.44 . So, (1.2)² = 1.44.
AikoMikan

Hey there!

Solve using pythagoras theorem (it's given that is triangle is right angled. Pythagoras theorem only works in the case of right triangles) ⇨ Hypotenuse² = Base² + Altitude ²

Here,

Base = 1.2 cm

Altitude = 1.6 cm

Hypotenuse = ? (let's take it as 'x' )

Hypotenuse² = Base² + Altitude ²

x² = (1.2)² + (1.6)²

x² = 1.44 + 2.56

x² = 4.00

x² = 4

x = √4

x = 2 cm.

Hope it helps ya!

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