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The ages of three brothers are consecutive, even integers. If the sum of the first even integer, three times the second even integer and twice the third even integer is fifty. Find the ages of all three brothers

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mondaymorningblues

Answer:

The ages of all three brothers are 4,6,8 years.

Step-by-step explanation:

Here n is the smallest of the three consecutive even integers, the condition gives you this equation

2n + 3*(n+2) + (n+4) = 34.

2n + 3n + 6 + n + 4 = 34

6n = 24

n = 4.

Answer. The ages are 4, 6 and 8 years.

Hope this helps you.

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