A single-phase load is located 2800 ft from its source. The load draws a current of 86 A and operates on 480 V. The maximum voltage drop at the load cannot be greater than 3%. What size aluminum conductors should be installed to operate this load?

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The size of aluminum conductors that should be installed to operate this load is equal to 570.059 Kilo-cmil.

Given the following data:

Length = 2800 ft.

Current = 86 A.

Voltage = 480 V.

How to determine the size of aluminum conductors?

First of all, we would calculate the maximum amount of voltage drop as follows:

E = 480 × 0.03

E = 14.4 Volts.

By applying Ohm's law, we would calculate the maximum amount of resistance as follows:

R = E/I

R = 14.4/86

R = 0.167 Ohms.

Next, we would determine the total length of the two conductors:

Total length = 2 × 2800

Total length = 5600 ft.

Now, we can determine the size of aluminum conductors:

CM = (KL)/R

CM = (17 × 5600)/0.167

CM = 570.059 Kilo-cmil.

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