Answer:
answer 7m/s^2
Explanation:
›»› The Acceleration of jumper = 7 m/s²
Given :
Initial velocity of jumper (u) = 0 m/s
Final velocity of jumper (v) = 10.5 m/s
Time taken by jumper (t) = 1.5 sec
To Find :
Acceleration of jumper (a) = ?
Required Solution :
→ Initial velocity (u) = 0 m/s (because jumper increase from zero)
† From first equation of motion
⇒ v = u + at
⇒ 10.5 = 0 + a × 1.5
⇒ 10.5 = 0 + 1.5a
⇒ 10.5 = 1.5a
⇒ a = 10.5/1.5
⇒ a = 7 m/s²
║Hence, the Acceleration of jumper is 7 m/s².║
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Additional Information :
★ First equation of motion :
⪼ v = u + at
Where,
v is the Final velocity in m/s.
u is the Initial velocity in m/s.
a is the Acceleration in m/s².
t is the Time taken in second.
★ Second equation of motion :
⪼ s = ut + ½ at²
Where,
s is the Distance travelled in m.
u is the Initial velocity in m/s.
a is the Acceleration in m/s².
★ Third equation of motion :
⪼ v² = u² + 2as
Where,
v is the Final velocity in m/s.
u is the Initial velocity in m/s.
a is the Acceleration in m/s².
s is the Distance travelled in m.
