[tex]\\ \sf\longmapsto (1-6i)+(12+i)[/tex]
[tex]\\ \sf\longmapsto 1-6i+12+i[/tex]
[tex]\\ \sf\longmapsto 1+12-6i+i[/tex]
[tex]\\ \sf\longmapsto 13-5i[/tex]
[tex]\sf{13+(-5i) }[/tex]
Step-by-step explanation:
we have to Simplify the expression(1 – 6i) + (12 + i) to a + bi form
[tex](1 – 6i) + (12 + i)\\\\1-6i+12+i\\\\1+12-6i+i\\\\13-5i\\\\13+(-5i)[/tex]
