amyclark1005 amyclark1005

10-10-2021
Mathematics

contestada

The equation 20x2=4kx−13kx2+2 where k is a constant, has no real roots. It can be shown that k satisfies the inequality 2k2+13k+20<0.
Find the set of possible values for k.

Respuesta :

modlinlangston6 modlinlangston6

10-10-2021

Answer:

16k with the little 2 by the k so like 16k2-4(2)(-5k)

Step-by-step explanation:

ANSWER IS -5/2<K<0.

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