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The tension t in a spring varies directly with the distance d the spring is stretched. If the
tension is 26 pounds when the spring is stretched 4 inches, find the tension when the spring is stretched twice as
far.

Respuesta :

Kittyhacker14

Answer:

t = 21d

Step-by-step explanation:

Here tension and distance are denoted t by d  and  respectively. Since  t varies directly with d , then the relation between  t and d is k=td Given that, for the tension 42 pounds, the spring is stretched 2 inches. Substituting  t = 42 and d= 2 into  t = kd find the value of k . Therefore,

42= K (2)

[tex]K=\frac{42}{2}[/tex]

K= 21

Thus the relationship is t = 21d

(Hope this helps can I pls have brainlist (crown)☺️)

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