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Answer:
$1.80, 2.90, 4.00, 10.90
not proportional
Step-by-step explanation:
For some distance d, we have a charge f(d) that is ...
[tex]f(d)=\begin{cases}1.00&0\le d\le0.1\\1.00+0.10\cdot\dfrac{(d-0.1)}{0.10}&0.1<d\end{cases}[/tex]
for d > 0.1, this simplifies to d +0.9.
Then the charges are ...
[tex]\begin{array}{cc}\underline{\text{miles}}&\underline{\text{charge}}\\9/10&1.80\\2&2.90\\3\ 1/10&4.00\\10&10.90\end{array}[/tex]
The different relation for the first 1/10 mile indicates ...
the relationship is not proportional.
