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<1 and <2 are supplementary. m<1 = 3x -4 and m<2 = 8x-14. Find the measure of each angle

a. m<1 = 130° , m<2 = 50°
b. m<1 = 50° , m<2 = 130°
c. m<1 = 110° , m<2 = 70°
d. m<1 = 70° , m<2 = 110°

Respuesta :

Blahblahblah1230
(3x-4)+(8x-14)= 180

11x-18=180
+18 +18
----------------

11x=198
x=18



m<1= 3(18)-4
m<1= 50

m<2=8(18)-14
m<2=130

Answer is B.

calculista

Answer:

The answer is the option b

[tex]m<1=50\°[/tex], [tex]m<2=130\°[/tex]

Step-by-step explanation:

we know that

If angle 1 and angle 2 are supplementary

then

their sum is equal to [tex]180\°[/tex]

so

[tex](3x-4)\°+(8x-14)\°=180\°[/tex] -------> solve for x

[tex](11x-18)\°=180\°[/tex]

[tex]11x=180\°+18\°[/tex]

[tex]x=198\°/11=18\°[/tex]

[tex]m<1=(3x-4)\°=(3*18-4)\°=50\°[/tex]

[tex]m<2=(8x-14)\°=(8*18-14)\°=130\°[/tex]

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