Conner and Jana are multiplying (3^5 6^8)(3^9 6^10).
Conner's Work
(3^5 6^8)(3^9 6^10) = 3^5+^9 6^8+^10 = 3^14 6^18

Jana's Work
(3^5 6^8)(3^9 6^10) = 3^5⋅9 6^8⋅10 = 3^45 6^80
Is either of them correct? Explain your reasoning.
(i dont rly get this question)



Respuesta :

Jana is correct, ............

Answer:

Conner's work is right.

Step-by-step explanation:

The given expression is

[tex](3^{5}6^{8}) (3^{9} 6^{10})[/tex]

To solve this products, we need to use power properties, like the one below

[tex]a^{m} a^{n}=a^{m+n}[/tex]

In words, the product between powers which have the same base, results in the same base and the exponent is the sum of the first two.

So, if we apply this property, we have

[tex](3^{5}6^{8}) (3^{9} 6^{10})=(3^{5}3^{9})(6^{8} 6^{10})=3^{5+9}6^{8+10}=3^{14}6^{18}[/tex]

Now, if we compare Conner's work and Jana's work, you will observe that Conner is right, because he applied the right property of powers to simplify the expression.

Therefore, Conner's work is right.