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11-01-2017
Physics

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A skydiver jumps from an airplane and falls freely for 5 seconds. If the sky diver's velocity increases by 49 m/s during that time, at which rate is the diver accelerating ?

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Katelynn05 Katelynn05

11-01-2017

Your answer would be 9.8

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11-01-2017

Acceleration = (change in speed) / (time for the change)

   =    (49 m/s) / (5 seconds)

   = (49 / 5) m/s / s

   =    9.8 m/s²

Answer Link

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