Using algebraic equations:
the number of sessions that will give same cost for both plans is: 1
the cost is: $96
Translate the situation into algebraic equations.
Equation for total cost of the first plan:
y = 41x + 55
Equation for the total cost of the second plan:
y = 46x + 50
To find the number of sessions that would yield same cost for both plans, make both equations equal to each other and solve for x.
41x + 55 = 46x + 50
41x - 46x = - 55 + 50
-5x = -5
x = 1
For a session, both plans will yield the same cost.
The cost 1 session will yield for both:
41x + 55 = 46x + 50
41(1) + 55 = 46(1) + 50
96 = 96
Therefore, using algebraic equations:
the number of sessions that will give same cost for both plans is: 1
the cost is: $96
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