cicixv26
contestada

A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
bead collides elastically with a larger 0.60 kg bead initially at rest. After the collision the smaller
bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead moves along
the wire in the first 5.0 s following the collision?||

Respuesta :

Answer:

Total momentum before collision

P1 =.4 * 3.5 = 1.4       ignoring units here

Total momentum after collision

P2 = .6 * V - .4 * .7 = .6 V - .28

.6 V = 1.4 + .28   momentum before = momentum after

V = 2.8 cm/sec

In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm