The net force on the box perpendicular to the floor is
∑ F[perp] = F[normal] - mg = 0
where mg is the weight of the box. Then
F[normal] = mg = 147 N
so that
F[friction] = 0.3 F[normal] = 44.1 N
The net force parallel to the floor is
∑ F[para] = F[applied] - F[friction] = ma
where a is the acceleration of the box. Then
F[applied] = (15 kg) a + 44.1 N
Then the work done by the applied force is
W[applied] = ((15 kg) a + 44.1 N) (1 m) = (15a + 44.1) J
We can't find the exact amount of work without any more information. If the box is pulled with constant speed, then a = 0 so the work would be 44.1 J.
