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The balanced equation for combustion in an acetylene torch is shown below: 2 upper c subscript 2 upper h subscript 2 plus 5 upper o subscript 2 right arrow 4 upper c upper o subscript 2 plus 2 upper h subscript 2 upper o. The acetylene tank contains 35. 0 mol c2h2, and the oxygen tank contains 84. 0 mol o2. How many moles of o2 are needed to react completely with 35. 0 mol c2h2? mol o2.

Respuesta :

The number of moles of O2 that are needed to react completely with 35.0 mol C2H2 is; 87.5 mol of O2

Combustion Reaction

We are given The equation for combustion in an acetylene torch as;

2C2H2 + 5O2 --> 4CO2 + 2H2O

We are given;

  • Acetylene tank contains 35.0 mol C2H2
  • Oxygen tank contains 84.0 mol O2.

From the balanced equation above, we can see that;

2 mol of C2H2 reacts with 5 mol of O2

Thus, by proportion;

If 2 mol C2H2 = 5 mol O2

Then;

35 mol C2H2 = 35 mol C2H2 × 5 mol O2/2 mol C2H2

>> 87.5 mol of O2

Read more about combustion reaction at;https://brainly.com/question/2658616

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