(-5[tex]x^{2}[/tex] -4x-1)+(-4[tex]x^{2}[/tex]-4x)
=-5[tex]x^{2}[/tex] -4x-1-4[tex]x^{2}[/tex]-4x
=-9[tex]x^{2}[/tex]-8x-1
Answer:
[tex]( - 5x^{2} \times - 4x \: - 1)( - 4^{2} - 4x)[/tex]
[tex](((0 - (5 • ( { \times }^{2} ))) - 4x) - 1) + ((0 - {2}^{2} {x}^{2} ) - 4x)[/tex]
[tex](((0 - 5 {x}^{2} ) - 4x) - 1) + ( - 4 {x}^{2} - 4x)[/tex]
Full out like factors:
[tex] - 9 {x}^{2} - 8x - 1 • = - 1(9 {x}^{2} + 8x + 1[/tex]
Factoring
[tex]9 {x}^{2} + 8x + 1[/tex]
The first term is, [tex]9 {x}^{2} [/tex] its coefficient is 9 .
The middle term is, [tex] + 8x[/tex] its coefficient is 8 .
The last term, "the constant", is [tex] + 1[/tex]
Step-1 : Multiply the coefficient of the first term by the constant 9 • 1 = 9
Step-2 : Find two factors of 9 whose sum equals the coefficient of the middle term, which is 8 .
[tex] -9x^2 - 8x - 1[/tex]
