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Select the correct answer. Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound? A. 2. 13 × 1023 B. 4. 26 × 1023 C. 2. 57 × 1024 D. 3. 37 × 1024 E. 7. 08 × 1024.

Respuesta :

Atoms are the smallest division of the element. The potassium atoms present in the 235 gm of the compound is [tex]2.57 \times 10^{24}[/tex] atoms.

What is the number of atoms?

Given,

  • Mass (m) of Potassium sulfide [tex](\rm K_{2}S)[/tex] = 235 gm
  • Molar mass (M) of  Potassium sulfide = 110.26 g/mol

Calculate the number of moles as:

[tex]\begin{aligned}\rm Moles (n) &= \dfrac{\rm mass}{\rm molar\;\rm mass}\\\\&= \dfrac{235}{110.26}\\\\&=2.13\;\rm mol\end{aligned}[/tex]

In the given compound [tex]\rm K_{2}S[/tex], there are two atoms of potassium and one atom of sulphur.

If, 1 mole = [tex]2 \times 6.022 \times 10^{23}[/tex] atoms of potassium

Then, 2.13 moles = X atoms

Solving for X:

[tex]2.13 \times 2 \times 6.022 \times 10^{23} = 2.57 \times 10^{24}[/tex]

Therefore, option c. [tex]2.57 \times 10^{24}[/tex] is correct.

Learn more about atoms here:

https://brainly.com/question/11411852

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