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Two pools are being filled with water. To start, the first pool contains 2164 liters of water and the second pool contains 2500 liters of water. Water is being added to the first pool at a rate of 31.75 liters per minute. Water is being added to the second pool at a rate of 21.25 liters per minute.

After how many minutes will the two pools have the same amount of water?

How much water will be in each pool when they have the same amount?

Respuesta :

MrRoyal

The amount of water in each pool at a particular time are illustrations of linear functions

  • Both pools will have the same amount of water after 32 minutes
  • Both pools will have 3180 liters at 32 minutes

How to determine the time they have the same amount

For the first pool, we have the following parameters

  • Initial amount = 2164 liters
  • Rate = 31.75 liters per minute

So, the equation of the amount of water in the pool is:

y = 2164 + 31.75x

For the second pool, we have the following parameters

  • Initial amount = 2500 liters
  • Rate = 21.25 liters per minute

So, the equation of the amount of water in the pool is:

y = 2500 + 21.25x

When both pools have the same amount of water, we have:

2164 + 31.75x = 2500 + 21.25x

Collect like terms

31.75x - 21.25x = 2500 - 2164

Evaluate the like terms

10.5x = 336

Solve for x

x = 32

This means that they will have the same amount of water after 32 minutes

Substitute 32 for x in y = 2164 + 31.75x

This gives

y = 2164 + 31.75 * 32

y = 3180

Both pools will have 3180 liters at 32 minutes

Read more about linear functions at:

https://brainly.com/question/15602982

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