When the thrust is increased, the acceleration of the motion is increased by 9.72 m/s².
The acceleration of the motion is determined as follows;
[tex]a = \frac{F}{m}[/tex]
where;
[tex]a = \frac{96,000}{9800} - \frac{80}{1,000} \\\\a = 9.8 - 0.08\\\\a = 9.72 \ m/s^2[/tex]
Thus, when the thrust is increased, the acceleration of the motion is increased by 9.72 m/s².
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