The force F shown in Figure 4.30 has a moment of 40 Nm about the pivot. Calculate the magnitude
of the force F.

[tex]\boxed{\sf \tau=rFsin\theta}[/tex]
Put values
[tex]\\ \rm\hookrightarrow 40=2Fsin40[/tex]
[tex]\\ \rm\hookrightarrow Fsin40=20[/tex]
[tex]\\ \rm\hookrightarrow 0.64F=20[/tex]
[tex]\\ \rm\hookrightarrow F=31.25N[/tex]