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A large school district found that 88 of 100 randomly selected students at East High School had internet access
at home. A separate random sample from West High showed 79 of 100 students had internet access at home.
Administrators used those results to make a 90% confidence interval to estimate the difference between the
proportion of students at each school who have internet access at home (PE - Pw). The resulting interval was
approximately 0.09 0.086. They want to use this interval to test H, : PE = Pw versus H : PE + Pw at
the a = 0.10 significance level. Assume that all conditions for inference have been met.
Based on the interval, what do we know about the corresponding P-value and conclusion at the a=0.10
level of significance?

Respuesta :

It can be deduced that the p-value is less than the level of significance.

What is a level of significance?

It should be noted that the level of significance simply means the measure of the strength of the evidence that's is present in a sample before the null hypothesis is rejected.

From the complete question, the confidence interval is a given as (0.004, 0.176). In this case, the p-value is less than the level of significance and they should conclude that there's a difference between the proportions.

Learn more about level of significance on:

https://brainly.com/question/4599596

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