[tex]\longrightarrow \sf \$ \: 307.2[/tex]
Since painting is done on outer surface of cubical block we will have to find its surface area which is given by-
[tex]\green{ \underline { \boxed{ \sf{Surface \: area \:of \:Cube = 6a^2}}}}[/tex]
[tex]\begin{gathered}\\\quad \sf Surface \: area \:of \:Cube = 6\times(3.2)^2 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies \quad \sf 6\times 3.2\times3.2 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies \quad \sf 61.44 cm^2 \\\end{gathered} [/tex]
Now,
[tex]\maltese \sf Cost \:of \:painting \: 1 \: cm² = \$ 5[/tex]
[tex] \sf Cost \: of \: painting \: 61.44 \:cm²=61.44×5[/tex]
[tex]\sf\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad=\$ 307.2[/tex]
[tex]\leadsto[/tex]Thus it would cost $ 307.2 to paint the entire cubical block.
