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asuwafohjames

The  [OH⁻] of the solution is 5.37×10⁵ M.

What is pOH?

This is the negative logarithm to base 10 of hydroxy ion [OH⁻] concentration.

To calculate the hydroxy ion [OH⁻] concentration we use the formula below.

Note:

  • pH+pOH = 14
  • pOH = 14-pH
  • pOH = 14-9.77
  • pOH = 4.27

Formula:

  • [OH⁻] = 1/[tex]10^{pOH}[/tex]................. Equation 1

Given:

  • pOH = 4.27

Substitute the value into equation 1

  • [OH⁻] = 1/[tex]10^{4.27}[/tex]
  • [OH⁻]  = 5.37×10⁵

Hence, The [OH⁻] of the solution is 5.37×10⁵ M.

Learn more about hydroxy ion concentration here: https://brainly.com/question/17090407

Eduard22sly

The concentration of the hydroxide ion [OH¯] in the solution is 5.89×10¯⁵ M

How to determine the pOH

From the question given above, the following data were obtained:

  • pH = 9.77
  • pOH =?

pH + pOH = 14

9.77 + pOH = 14

Collect like terms

pOH = 14 – 9.77

pOH = 4.23

How to determine [OH¯]

  • pOH = 4.23
  • Concentration of Hydroxide ion [OH¯] =?

pOH = –Log [OH¯]

4.23 = –Log [OH¯]

Multiply through by –1

–4.23 = Log [OH¯]

Take the anti-log of –4.23

[OH¯] = anti-log (–4.23)

[OH¯] = 5.89×10¯⁵ M

Learn more about pH:

https://brainly.com/question/3709867

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