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What is the concentration of Ni2+(aq) ion in a 0.035 M Ni(NO3)2 solution that is also 1.00 M NH3? (Kf for Ni(NH3)6 ^2+ = 5.5 × 108)
a) 3.5 × 10–2 M
b) 6.4 × 10–11 M
c) None of these is correct.
d) 2.6 × 10–10 M
e) 7.9 × 10–11 M

Respuesta :

okpalawalter8

The concentration of X2+(aq) ion is mathematically given as

X^{2+}=3*10^{-10}M

What is the concentration of X2+ ion?

Question Parameters:

the concentration of X2+(aq) ion in a 0.035 M (NO3)2 solution

Generally, the equation for the Chemical Reaction  is mathematically given as

X2+ + 6xH3--><--- (X(xH_3)_6)^2+

Therefore

X^{2+}=(X (xH_3) _6)^{2+}) /(x ^{2+})+(xH_3^6)

[tex]X^{2+}=\frac{0.375}{5.5*10^8*0.79^6}[/tex]

X^{2+}=3*10^{-10}M

Hence, we have that the  concentration of Ni2+(aq) ion is X^{2+}=3*10^{-10}M

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