Hi there!
Recall the following relationship between the electric field and electrical potential:
[tex]E = -\frac{dV}{dx}[/tex]
Begin by taking the derivative of the electric potential function using basic power and constant rules.
Remember:
[tex]\frac{dy}{dx}x^n = nx^{n - 1}[/tex]
[tex]\frac{dy}{dx}(C) = 0[/tex]
Differentiate the function, and take its negative.
[tex]-\frac{dV}{dx} = -(2(1)(x^{1-1}) + 0 )\\\\-\frac{dV}{dx} = -2[/tex]
The magnitude is the absolute value, so:
[tex]|\frac{dV}{dx} = |-2| = \boxed{2 \frac{V}{m}}[/tex]
