Answer:
[tex]\huge\boxed{\bf\: 83 \: yd^{2}}[/tex]
Step-by-step explanation:
Consider rectangle ABCD.
Here,
AB = DC = 9 yd (length = l)
AD = BC = 7 yd (width = w)
Area of this rectangle:
= l * b
= 9 * 7
= 63 yd²
[tex]\rule{150pt}{2pt}[/tex]
Now, take rectangle DEGF.
Here,
DE = FG = 5 yd (length = l)
DF = EG = 4 yd (width = w)
Area of this rectangle:
= l * b
= 5 * 4
= 20 yd²
[tex]\rule{150pt}{2pt}[/tex]
Total area of the compisite figure:
= Area of rectangle ABCD + Area of rectangle DEGF
= 63 yd² + 20 yd²
= 83 yd²
[tex]\rule{150pt}{2pt}[/tex]
- Refer to the attachment for the labelling of the figure.
