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If f(x) = 10x^3-37x^2+15x+18 and x-3 is a factor of f(x), then find all of the zeros of f(x) algebraiclly.

Respuesta :

dylannelson259

Answer:

x=6/5 and x=-(1/2)

Step-by-step explanation:

[tex]f(x) = 10x^3-37x^2+15x+18\\f(x) = \frac{(5x-6)(2x+1)(x-3)}{(x-3)}\\ f(x) = (5x-6)(2x+1)[/tex]

To find the zeros, we set f(x) = 0 for both factors

[tex]5x-6=0\\5x=6\\x=6/5[/tex]

[tex]2x+1=0\\2x=-1\\x=-1/2[/tex]

Therefore the zero's of f(x) are x = 6/5 and x= -(1/2)

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