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What is the equation of the line that passes through the point (4,-6) and has a slope of -5/2?


Please I’m desperate I already tried and it was wrong I’ll mark Brainlist

Respuesta :

Mohamed1429

Answer:

y = (-5/2)X + 4

Step-by-step explanation:

we know that the equation of a line is y = mx + b

m = -5/2

so

y = -5/2x + b

to find b:

-6 = -10 + b

b = 4

so

y = (-5/2)X + 4

semsee45

Answer:

Use the point-slope form of a linear equation:

[tex]y-y_1=m(x-x_1)[/tex]

where:

  • [tex]m[/tex] = slope
  • [tex](x_1,y_1)[/tex] = point on line

Given:

  • [tex]m=-\dfrac52[/tex]
  • [tex](x_1,y_1)=(4,-6)[/tex]

Substitute given information into the equation:

[tex]\implies y-y_1=m(x-x_1)[/tex]

[tex]\implies y-(-6)=-\dfrac52(x-4)[/tex]

[tex]\implies y+6=-\dfrac52x+10[/tex]

[tex]\implies y=-\dfrac52x+4[/tex]

Therefore, the equation of the line in different formats is:

[tex]\textsf{slope-intercept form: }y=-\dfrac52x+4[/tex]

[tex]\textsf{standard form: }5x+2y=8[/tex]

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