Answer:
x=12,y=6√3
Step-by-step explanation:
[tex]let \: the \: angle \: be \: \alpha \\ \tan( \alpha ) = \frac{p}{b} \\ \tan( 60 ) = \frac{y}{6} \\ \sqrt{3} = \frac{y}{6} \\ y = 6 \sqrt{3} \\ now \: by \: using \: pythagoras \: theorem \: \\ x = \sqrt{(6 \sqrt{3) {}^{2} } } + (6) {}^{2} \\ x = \sqrt{108 + 36} \\ x = 12[/tex]
