Answer:
[tex]\frac{\sqrt{3} }{4}[/tex]
Step-by-step explanation:
[tex]\frac{1}{1+\sqrt{3} }[/tex]
basically we want to get rid of the √3 on the denominator
to do so we multiply it by itself so it is a perfect square
but whatever we do to the top we must do to the bottom so we multiply the numerator and denominator by √3
[tex]\frac{1*\sqrt{3} }{1+\sqrt{3}*\sqrt{3} }=\frac{\sqrt{3} }{1+\sqrt{9} } =\frac{\sqrt{3} }{1+3} =\frac{\sqrt{3} }{4}[/tex]
notes : √3 × √3 = √9 which is a perfect square that simplfies to 3
