√(4/7)^2 =
equations with square roots and cube roots

Answer:
See below
Step-by-step explanation:
If you are squaring a number, and then taking the square root of it, you are essentially undoing the original operation:
[tex]\displaystyle \sqrt{\biggr(\frac{4}{7}\biggr)^2}=\biggr[\biggr(\frac{4}{7}\biggr)^2\biggr]^{\frac{1}{2}}=\biggr(\frac{4}{7}\biggr)^{2*\frac{1}{2}}=\frac{4}{7}[/tex]
Hence, we are back starting with the original number