From the section formula, it was found that the coordinate for the point S is (12,21).
The coordinates of the point S which divides the line AB into two sections can be found from the application of the Section Formula that is presented below:
[tex]S=(\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n})[/tex], where
[tex]ratio=\frac{m}{n}[/tex]
[tex]x_1[/tex] and [tex]y_1[/tex] are coordinates of A
[tex]x_2[/tex] and [tex]y_2[/tex] are coordinates of B
The question gives r=[tex]\frac{3}{2}[/tex], A=(21,3) and B=(6,33). From the ratio, you can find m=3 and n=2.
Next step, applying the internal section formula. Then, you have:
[tex]S=(\frac{3*6+2*21}{3+2}, \frac{3*33+2*3}{3+2})\\ \\ S=(\frac{18+42}{5}, \frac{99+6}{5})\\ \\ S=(\frac{60}{5}, \frac{105}{5})\\ \\ S=(12, 21)[/tex]
Read more about the section formula here:
https://brainly.com/question/14812336
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