The mass of [tex]Na_2CO_3[/tex] that will be required to be dissolved in water would be 15.9 grams
Solution preparation
Recall that: molarity = mole/volume in L
In this case, the volume is 0.3 L and the molarity is 0.5 M.
Thus, mole = molarity x volume = 0.5 x 0.3 = 0.15 moles
Mass of 0.15 moles [tex]Na_2CO_3[/tex] = 0.15 x 106 = 15.9 grams
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