By eliminating the parameter t and evaluating the function at x = -1 we conclude that the parametric equations contains the point (x, y) = (-1, 0).
In this case we must determine if a point in rectangular format belongs to a set formed by two parametric functions. The functions are parametric as they are based in a parameter t. A quick approach consist in reduce the number of equations by eliminating the parameter.
The first equation is represented below:
t = x/3
And the parameter is substituted in the second equation:
y = 18 · (x/3)² + 12 · (x/3) + 2
y = 2 · x² + 4 · x + 2
If we know that x = -1, then the y-value is:
y = 2 · (- 1)² + 4 · (- 1) + 2
y = 0
By eliminating the parameter t and evaluating the function at x = -1 we conclude that the parametric equations contains the point (x, y) = (-1, 0).
The statement is incomplete, the complete definition is presented below:
Which of the following is a point on the plane curve defined by the parametric equations?
x = 3 · t, y = 18 · t² + 12 · t + 2
A. (-1, 0)
B. (-3, -28)
C. (-1, 8)
D. (-3, 128)
To learn more on parametric equations: https://brainly.com/question/12718642
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