The sampling distribution of the mean if all possible random samples of size 50 were chosen will be 0.731.
From the information given, the mean of all the possible sample means will be:
= 5.17/✓50
= 5.17/7.071
= 0.731
It should be noted that the sample means will have the same mean as the population.
The intervals that you would expect to contain the true mean will be:
= 0.95 × 250
= 237.5 intervals
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