The system of equations that have a solution of (-2,-2,-2) is (b) x + 2y = -6, y + 2z = -6 and x - y - z = 2
How to determine the system of equations?
The attached figure represents the proper format of the equations.
The solution is given as:
(x,y,z) = (-2,-2,-2)
To determine the system of equation, we simply substitute the values of x, y and z in the equations in the options.
So, we have:
Option 1:
x + y = 0
y - z = -2
x + y - z = -4
Evaluate
x + y = 0
-2 - 2 = 0 --- False
This means that this system of equations do not have a solution of (-2,-2,-2)
Option 2:
x + 2y = -6
y + 2z = -6
x - y - z = 2
Evaluate
x + 2y = -6
-2 + 2 * -2 = -6 --- True
y + 2z = -6
-2 + 2 * -2 = -6 ---- True
x - y - z = -2
-2 + 2 + 2 = 2
This means that this system of equations have a solution of (-2,-2,-2)
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