The probability of rain on the last day of July is 95 % . If the probability remains constant for the first seven days of August , what is the probability that it will rain at most two of those seven days in August ? Find the Mean , Standard Deviation , and Variance .

The probability of rain on the last day of July is 95 If the probability remains constant for the first seven days of August what is the probability that it wil class=

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The probability that it rains at most 2 days is 0.00005995233 and the variance is 0.516

The probability that it rains at most 2 days

The given parameters are:

  • Number of days, n = 7
  • Probability that it rains, p = 95%
  • Number of days it rains, x = 2 (at most)

The probability that it rains at most 2 days is represented as:

P(x ≤ 2) = P(0) + P(1) + P(2)

Each probability is calculated as:

[tex]P(x) = ^nC_x * p^x * (1 - p)^{n - x}[/tex]

So, we have:

[tex]P(0) = ^7C_0 * (92\%)^0 * (1 - 92\%)^{7 - 0} = 0.00000002097[/tex]

[tex]P(1) = ^7C_1 * (92\%)^1 * (1 - 92\%)^{7 - 1} = 0.00000168821[/tex]

[tex]P(2) = ^7C_2 * (92\%)^2 * (1 - 92\%)^{7 - 2} = 0.00005824315[/tex]

So, we have:

P(x ≤ 2) =0.00000002097 + 0.00000168821 + 0.00005824315

P(x ≤ 2) = 0.00005995233

Hence, the probability that it rains at most 2 days is 0.00005995233

The mean

This is calculated as:

Mean = np

So, we have:

Mean = 7 * 92%

Evaluate

Mean = 6.44

Hence, the mean is 6.44

The standard deviation

This is calculated as:

σ = √np(1 - p)

So, we have:

σ = √7 * 92%(1 - 92%)

Evaluate

σ = 0.718

Hence, the standard deviation is 0.718

The variance

We have:

σ = 0.718

Square both sides

σ² = 0.718²

Evaluate

σ² = 0.516

This represents the variance

Hence, the variance is 0.516

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