A) the wind is blowing directly towards the wind turbine at a speed of 12 m/s. at this wind
speed, 7500 kg of air passes every second through the circular area swept out by the
blades.
() calculate the kinetic energy of the air travelling at 12m/s, which passes through
the circular area in 1 second.

Respuesta :

The kinetic energy of the air travelling at 12m/s, which passes through

the circular area in 1 second is 5.4 x 10⁵ J.

What is kinetic energy?

The kinetic energy of an object is associated with its motion. It can be related to the mass and velocity as

K.E = 1/2 mv²

Given the wind is blowing directly towards the wind turbine at a speed of 12 m/s. At this wind speed, 7500 kg of air passes every second through the circular area swept out by the blades.

Substitute the values, we have

K.E = 1/2 x 7500 x (12)²

K.E = 5.4 x 10⁵ J

Hence, the kinetic energy of the air travelling at 12m/s, which passes through the circular area is  5.4 x 10⁵  J.

Learn more about kinetic energy.

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