Step-by-step explanation:
We are given a right angle triangle. So, we will use trigonometry.
sin 45 = opp/hyp
sin 45 = x/6√2
[tex] \frac{1}{ \sqrt{2} } = \frac{x}{6 \sqrt{2} } \\ [/tex]
[tex] \sqrt{2} x = 6 \sqrt{2} \\ [/tex]
[tex]x = \frac{6 \sqrt{2} }{ \sqrt{2} } \\ [/tex]
x = 6
Now, for y
cos 45 = adj/hyp
cos 45 = y/6√2
[tex] \frac{1}{ \sqrt{2} } = \frac{y}{6 \sqrt{2} } \\ [/tex]
[tex] \sqrt{2} y= 6 \sqrt{2} \\ [/tex]
[tex]y= \frac{6 \sqrt{2} }{ \sqrt{2} } \\ [/tex]
y = 6
