Respuesta :

xpepzikittyz

Answer:

C log(1/5)

Step-by-step explanation:

log 3-log 15 = -log _10^(5)

log 5 = log _10^(5)

log (-12) = log _10^(-12)

log (1/5) = -log _10^(5)

log 12 = log _10^(12)

Answer:

[tex]C. =log\frac{1}{5}[/tex]

Step-by-step explanation:

Formula =======================

consider a and b two real numbers

where a > 0 and b > 0.

[tex]log\frac{a}{b} =loga-logb[/tex]

……………………………………………………………

log 3 − log 15

[tex]=log\frac{3}{15}[/tex]

[tex]=log\frac{3}{3\times 5}[/tex]

[tex]=log\frac{1}{5}[/tex]

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