The quadratic function that passes through the point (0,6), (3,15.8), and (9.5,0) is y = -0.6x² + 5.07x + 6
How to determine the quadratic function?
The points are given as:
(0,6), (3,15.8), and (9.5,0)
A quadratic function is represented as:
y = ax² + bx + c
Next, we substitute the points in the equation.
a(0)² + b(0) + c = 6
a(3)² + b(3) + c = 15.8
a(9.5)² + b(9.5) + c = 0
Simplify the expressions
c = 6
9a + 3b + c = 15.8
90.25a + 9.5b + c = 0
Solve for a, b and c using a graphing calculator
a = -0.6
b = 5.07
c = 6
Hence, the quadratic function is
y = -0.6x² + 5.07x + 6
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