Hi student, let me help you out! :)
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We are asked to find the value of [tex]\mathrm{36x-8y^2}[/tex] when x=3 and y=-6.
So, we substitute the values of the variables instead of the variables:
[tex]\mathrm{36(3)-8(-6)^2}[/tex]
Square -6 first:
[tex]\mathrm{36(3)-8\times36}[/tex]
Multiply 36 times 3 and 8 times 36:
[tex]\mathrm{108-288}[/tex]
Upon subtraction, we obtain
[tex]\bigstar~\mathrm{\underline{-180}}[/tex]
Hope it helps you out! :D
Ask in comments if any queries arise.
#StudyWithBrainly
~Just a smiley person helping fellow students :)
