Mamadou spots an airplane on radar that is currently approaching in a straight line, and that will fly directly overhead. The plane maintains a constant altitude of 7325 feet. Mamadou initially measures an angle of elevation of 15^{\circ}

to the plane at point AA. At some later time, he measures an angle of elevation of 42^{\circ}

to the plane at point BB. Find the distance the plane traveled from point AA to point BB. Round your answer to the nearest foot if necessary.

Mamadou spots an airplane on radar that is currently approaching in a straight line and that will fly directly overhead The plane maintains a constant altitude class=

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The distance the plane traveled from point A to point B will be 19202 feet.

What is a right-angle triangle?

It's a form of a triangle with one 90-degree angle that follows Pythagoras' theorem and can be solved using the trigonometry function.

Mamadou spots an airplane on the radar that is currently approaching in a straight line, and that will fly directly overhead.

The plane maintains a constant altitude of 7325 feet.

Mamadou initially measures an angle of elevation of 15° to the plane at point A.

At some later time, he measures an angle of elevation of 42° to the plane at point B.

Then the distance the plane traveled from point A to point B will be

AB = CD

AB = EC - ED

The value of EC will be

tan 15° = 7325 / EC

     EC = 27337.3 feet

Similarly, the value of DE will be

tan 42° = 7325 / DE

     DE = 8135.2 feet

Then the distance the plane traveled from point A to point B will be

AB = 27337.3 - 8135.2

AB = 19202.1 feet

AB ≅ 19202 feet

More about the right-angle triangle link is given below.

https://brainly.com/question/3770177

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