What is the electric force acting between two charges of -0.0080 C and k9,92 and k = 9.00 × 10⁹ Nm²/C². 0.0050 C that are 0.035 m apart? Use F A. 1.0 × 107 N B. -2.9 × 108 N C. -1.0 × 107 N D. 2.9 × 108 N

The electric force acting between two charges will be -2.9 ×10⁹ C.Option B is correct.
The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.
The electric force acting between two charges will be ;
[tex]\rm F = K\frac{q_1q_2}{r^2} \\\\ \rm F = 9 \times 10^9 \frac{(-0.0080)^2}{(0.035)^2}\\\\F=2.98 \times 10^{9} \ N[/tex]
Hence option B is correct.
To learn more about Columb's law refer to the link;
https://brainly.com/question/16557916
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