What is the electric force acting between two charges of -0.0080 C and k9,92 and k = 9.00 × 10⁹ Nm²/C². 0.0050 C that are 0.035 m apart? Use F A. 1.0 × 107 N B. -2.9 × 108 N C. -1.0 × 107 N D. 2.9 × 108 N​

What is the electric force acting between two charges of 00080 C and k992 and k 900 10 NmC 00050 C that are 0035 m apart Use F A 10 107 N B 29 108 N C 10 107 N class=

Respuesta :

The electric force acting between two charges will be -2.9 ×10⁹ C.Option B is correct.

What is Columb's law?

The force of attraction between two charges, according to Coulomb's law, is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Charges that are similar repel each other, whereas charges that are diametrically opposed attract each other.

The electric force acting between two charges will be ;

[tex]\rm F = K\frac{q_1q_2}{r^2} \\\\ \rm F = 9 \times 10^9 \frac{(-0.0080)^2}{(0.035)^2}\\\\F=2.98 \times 10^{9} \ N[/tex]

Hence option B is correct.

To learn more about Columb's law refer to the link;

https://brainly.com/question/16557916

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