Answer:
C
Step-by-step explanation:
9x² - 4[tex]y^{6}[/tex]
can be factored as a difference of squares , that is
(U + V)(U - V)
9x² - 4[tex]y^{6}[/tex] = (3x)² - (2y³)²
with U = 2x and V = 2y³
U= 3x and V=2y^3
9x^2= (3x)^2
4y^6 = (2y^3)^2
=(3x)^2 - (2y^3)^2
Apply this rule below
x^2 - y^2 = (x + 7) - (x - y)
(3x)^2 - (2y^3)^2 = (3x + 2y^3) + (3x - 2y^3)
= (3x + 2y^3) (3x - 2y^3)
