The average rate of change of the function from n = 1 to n = 5 is 3.36 plants per day
The function is given as:
f(n) = 10(1.02)^n
The maximum height is 11.04
So, we have:
10(1.02)^n = 11.04
Divide by 10
1.02^n = 1.104
Take the log of both sides
n * log(1.02) = log(1.104)
Divide by log(1.02)
n = 5
Hence, the reasonable domain is 0 ≤ n < 5
We have:
f(n) = 10(1.02)^n
Set n to 0
f(0) = 10(1.02)^0
Evaluate
f(0) = 10
Hence, the y-intercept is 10
We have:
f(n) = 10(1.02)^n
Calculate f(1) and f(5)
f(1) = 10(1.02)^1 = 10.2
f(5) = 10(1.02)^5 = 10.2
The average rate is then calculated as:
m = (f(5) - f(1))/(5 - 1)
This gives
m =(11.04 - 10.2)(5 - 1)
Evaluate
m = 3.36
Hence, the average rate of change of the function f(n) from n = 1 to n = 5 is 3.36
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